Question

The sum of three consecutive integers is 48. Frame an equation for the given situation and then find these numbers.​

Answer 1

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Answer 2

Answer:

ஃ The first number = x = 15

The second number = x + 1 = 15 + 1 = 16

The third number = x + 2 = 15 + 2 = 17

Step-by-step explanation:

Let the number be 'x'

x + ( x + 1 ) + ( x + 2 ) = 48

3x + 3 = 48

3x = 48 - 3 = 45

3x = 45

$\sf x = \frac{ \cancel{45}}{ \cancel{3}} = 15$

Check:-

x + ( x + 1 ) + ( x + 2 ) = 48

15 + ( 15 + 1 ) + ( 15 + 2 ) = 48

15 + 16 + 17 = 48

48 = 48