Question

The sum of three consecutive integers is 5 more than the smallest of the integers. Find the integers.

Answer 1

Let us assume, the three consecutive integers are n, n+1 and n+2, where n is a positive integer

Given:

n + n + 1 + n + 2 = n + 5

3n + 3 = n + 5

2n = 2

n = 1

Therefore, the three consecutive intergers are 1, 2 and 3

Answer 2

Answer:

Step-by-step explanation:

Let the smallest integer be x

Then according to question,

=> x + x + 1 + x + 2 = x + 5

=> 3x + 3 = x + 5

=> 3x - x = 5 - 3

=> 2x = 2

=> x = 1

The integers are-

x = 1

x + 1= 1+1 =2

x +2= 1+2=3

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