Question

the sum of three consecutive integers is 600.find these integers​

Answer 1

Answer:

Let x be the first unknown number. The numbers are consecutive, so the other two would be; x+1, x+2

We now have:

x+(x+1)+(x+2)=600

Now we solve the equation for x,

We can add all the x's together; 3x+3=600

Now we subtract the 3 from both sides;

3x+3-3=600-3

3x = 597

Now we divide the 3 from both sides;

3x/3 = 597/3

We are left with x=199

check:

now we can add the numbers placing 199 for x;

199+(199+1)+(199+2)=600

Answer 2

Answer:

Step-by-step explanation:

x + x + 1 + x + 2 = 600

x + x + x + 1 + 2 = 600

3x + 3 = 600

We can pass (+3) to the other member of the equation as we invert the signal:

3x = 600 - 3

3x = 597

x = 597/3

x =199

As I sad before, x is the smaller number of the three consecutive numbers, so, the consecutives numbers that sums up to 600 are 199, 200 and 201.

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