the sum of three consecutive integers is 78. find them
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Answered by
8
let first number be x
so second be x+1
so third be x+2 because they are consecutive
so x+x+1+x+2=78
3x+3=78
3x=78-3
x=75/3
x=25
so the numbers will be 25,26,27
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Answered by
4
Answer:
Let 1st no. be = x
2nd no. = x+1
And 3rd no. =x+2
A/q,
x+(x+1)+(x+2)= 78
3x+3=78
3x=75
x=25
Therefore, 1st no. is 25
2nd no. Is 26 and 3rd no. Is 27
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