Question

The sum of three consecutive integers is five more than the smallest of the integer. Find the three integers

Answer 1

x-1+x+x+1=x-1+5
3x=x+4
2x=4
x=2

Answer 2

$\mathbf{ Let \: \: integers \: \: are \: \: [ x(smallest ) \: , \: ( x + 1 ) \: , \: ( x + 2 ) ] }$




According to the question,


$\bold{Sum \: \: of \: \: all \: \: three \: \: integers = 5 + smallest \: \: integer }$



=> x + x + 1 + x + 2 = 5 + x

=> 3x + 3 = 5 + x

=> 3x - x = 5 - 3

=> 2x = 2

$= > \bold{x = 1}$

Hence, Integers are :

x = 1
x + 1 = 1 + 1 = 2
x + 2 = 1 + 2 = 3