Question

the sum of three consecutive integers is twice the smallest of the integer find the integer​

Answer 1

Answer:

let the three consecutive no. be x, x+1 and x+2

then A/Q

x+x+1+x+2=2x

3x+1+2=2x

3x-2x=-3

x=-3

hence the three no. are -3,-2,-1

Answer 2

SoluTion:

It is given that, sum of three consecutive Integers is twice the smallest integer.

Let the integers be x, x+1 and x+2.

According to Question,

→ x + x + 1 + x + 2 = 2x

→ 3x + 3 = 2x

→ 3x - 2x = -3

→ x = -3

Hence, three consecutive integers are -3, -2 and -1.

__________________________

VerificaTion:

→ -3 + (-2) + (-1) = 2(-3)

→ -3 - 2 - 1 = -6

→ -6 = -6

Verified.