Question

the sum of three consecutive integers multiples of 3 is 99 .find the multiples​

Answer 1

Answer:

i anwser you

Step-by-step explanation:

Answer 2

Answer:

30,33,36 is your answer

Step-by-step explanation:

• let the first term is 3n
• and the others are 3n+3,3n+6
• according to the question, 3n+3n+3+3n+6=99
• => 9n+9=99
• => 9(n+1)=99
• => n+1=11
• => n=10
• now the first number is = 3*10=30
• second number is = 30+3=33
• third number is = 30+6=36
• the number sequence is 30,33,36(Ans.)
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