Question

The sum of three consecutive integers multiples of 8 is 888.find the multiples

Answer 1

Answer:

888/24

Step-by-step explanation:

Let us take no. to be 8x

8x+(8x+1)+(8x+2)=888

24x+3=888

24x=888-3=885

x=885/24

Answer 2

Let the three consecutive integer multiples of 8 be X , X + 8 , X + 16

Given sum of those multiples = 888

=> X + X + 8 + X + 16 = 888

=> 3X + 24 = 888

=> 3X = 864

=> X = 288

∴ The three consecutive integer multiples of 8 are 288 , 296 , 304