Question

the sum of three consecutive mulitiples of 7 is 126 what sre the consicutive mutiples​

Answer 1

Answer:

7n+7n+7+7n+14=126

21n+21=126

21n=105

n=5

7⋅5+14=49

The greatest is 49.

\begin{lgathered}2n+2n+2+2n+4=84\\ 6n+6=84\\ 6n=78\\ n=13\\\\ 2\cdot13=26

2n+2n+2+2n+4=84

6n+6=84

6n=78

n=13

2⋅13=26

The least is 26.

Answer 2

SO THREE NO. ARE=

7x + (7x+7) + (7x+14)=126

21x+21=126

21x=105

x=5

then threre multiplies are=

35 , 42 and 49.