Question

பு The sum of three consecutive multiple of
11 is 36. find these multiple

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Answer 1

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=

33

330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132

Answer 2

Step-by-step explanation:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=

33

330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110

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