Question

The sum of three consecutive multiple of 11 is 363.find these multiple

Answer 1

Answer:

11a+11(a+1)+11(a+2)

=363

so 33a + 11 + 22 = 363

33a + 33 = 363

a+1=363/33

=11

so a=10

so

multiples are

110

121

and

132 ANSWER

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.