The sum of three consecutive multiple of 11 is 363 find these multiple
Answers
Let us assume that the smallest multiple to be 11x, where x is any natural number.
Hence, we can say the other numbers are: 11(x+1) and 11(x+2) as they are consecutive multiples.
So from he question: 11x+11(x+1)+11(x+2)=363
11x+11x+11+11x+22=363
33x+33=363
x+1=363/33
x+1=11
Therfore, x=10
On substituting the value of x in the numbers,
11x=110
11(x+1)=121
11(x+2)=132
Answer: 110 , 121 and 132
Step-by-step explanation:
Let the number's be x , x+11 , x+22.
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
x = 330/3 = 110
x + 11 = 110 + 11 = 121
x + 22 = 110 + 22 = 132
Hence, the number's are 110 ,121 and 132.