Question

The sum of three consecutive multiple of 11 is 363 find these number

Answer 1

Three consecutive multiples are 110,121 and 132 which has the sum of 363.

Solution:

Let us take the first number as 11 (C – 1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 363

Now the sum of 3 numbers are 11C + 11(C – 1) + 11(C + 1) = 363

33C = 363;  C = 33,  

By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

Answer 2

Answer:

110,121,132

Step-by-step explanation:

let the first multiple be 11x

11x+11(x+1)+11(x+2)=363

11x+11x+11+11x+22=363

33x+33=363

33x=363-33

33x=330

x=10

1st integer=11x=11*10=110

2nd integer=11(x+1)=110+11= 121

3rd integer=11(x+2)=132