Question

The sum of three consecutive multiple of 11 is 363. find these multiply
(a) 117,121,125
(b) 110,121,132
(c) 110,99,154
(d) 154,88,121​

Answer 1

Answer:

b

Step-by-step explanation:

11(x)+11(x+1)+11(x+2)=363

11(x+x+1+x+2)=363

3x+3=33

3x=30

x=10

multiples are 11(10),11(11),11(12)

i.e.,110,121,132

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.

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