Question

The sum of three consecutive multiple of 11 is 363 . Find these multiplies ?​

Answer 1

Answer:

Let the first multiple be 11x

then, second multiple be 11 ( x + 1 )

= 11x + 11

and third multiple be 11 ( x + 2 )

= 11x + 22

According to question :-

11x + ( 11x + 11 ) + ( 11x + 22 ) = 363

33x + 33 = 363

33x = 363 - 33

33x = 330

x = 330/33

x = 10

hence, the first multiple = 11x = 11 × 10

= 110

second multiple = 11x + 11 = 110 + 11

= 121

third multiple = 11x + 22 = 110 + 22

= 132

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