Question

The sum of three consecutive multiple of 11 is 363 . find the multiplies ..​

Answer 1

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Hie mate!!

your answer is ______

↪let the first multiple be x

therefore the multiples are x, x +11, x +22

》therefore x + x +11+ x +22 = 363

》3x +33 = 363

》3x = 330

》x = 110

》 x +11 = 110 + 11 = 121

》 x +22 = 110 + 22 = 132

Answer 2

Let First of the consecutive Multiple of 11 is =X

Then Second=(x+11)

Third=(x+11+11)=(x+22)

Why We are Adding 11.

Let UNDERSTAND By a Example.

11×1=11

11×2=22

Difference=11

11×3=33

Difference is 11

As 22+11=33

So We get 3 Consecutive Multiple as

x,x+11,x+22

Sum=363

x+x+11+x+22=363

3x+33=363

3x=363-33

3x=330

x=330/3

x=110

We get X=110

Second Multiple =x+11=110+11=121

Third Multiple=x+22=110+22=132

Multiples=110,121,132