Question

The sum of three consecutive multiple of 11 is 363. Find thes multiple

Answer 1

let the numbers be 11x,11(x+1),11(x+2)

Given, 11x+ 11x+11+11x+22=363

33x = 330

x=10

the multiples are 110,121,132

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Answer 2

Answer:

Let , the first consecutive multiple be x

the second consecutive multiple be x+11

the third consecutive multiple be x+22

A/Q,

= x + x+11 + x+22 = 363

= 3x + 33 = 363

= 3x = 363 - 33

= 3x = 330

= x = 330/3

= x = 110

Therefore,

The first consecutive multiple = x = 110

The second consecutive multiple = x+11

= 110+11 = 121

The third consecutive multiple = x+22

= 110+22 = 132