Question

The sum of three consecutive multiple of 11 is 468. Find the multiple.

Answer 1

Answer:

★ In the Question there is 462 not 468

Let us take the first number as 11(C-1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 468

11C + 11(C – 1) + 11(C + 1) = 468

33C = 468

C = 14

By substituting C = 14 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 154 , 143 and 165

Answer 2

★ In the Question there is 462 not 468

Let us take the first number as 11(C-1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 468

11C + 11(C – 1) + 11(C + 1) = 468

33C = 468

C = 14

By substituting C = 14 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 154 , 143 and 165....