The sum of three consecutive multiple of 5 is 45. Which is the smallest of the three multiple
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Let the three consecutive multiples are x,x+5 and x+10
now,according to question,
x+x+5+x+10=45
3x+15=45
3x=45-15
3x=30
x=30/3=10
one multiple=10
2nd multiple=10+5=15
3rd multiple=10+10=20
the smallest multiple=10
HOPE IT HELPS YOU
Let the three consecutive multiples are x,x+5 and x+10
now,according to question,
x+x+5+x+10=45
3x+15=45
3x=45-15
3x=30
x=30/3=10
one multiple=10
2nd multiple=10+5=15
3rd multiple=10+10=20
the smallest multiple=10
HOPE IT HELPS YOU
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