Question

the sum of three consecutive multiple of 6 is 864 find these multiples

Answer 1

Let the 3 consecutive multiples be x,x+6andx+12
Acc to question
X+X+6+X+12=864
3X+18=864
3X=864-18
3X=846
X=846/3
X=282

So the 1 multiple is X=282
2 multiple=X+6=282+6=288
3 multuple=X+12=294
Verification--
282+288+294=864
Hence verified also...plz mark as brainliest if it help u...

Answer 2

Here is your solution

Let,

The first multiple of 6 be x 

Second multiple = x+6 

Third multiple = x+6+6 = x+12 

A/q

x+x+6+x+12 = 864
=>3x + 18 = 864
=>3x = 864-18 = 846
=>x = 846/3 
=>x = 282

Hence,
x=282
x+6 = 288
x+12 = 294

So, the multiples are 282, 288 and 294.
 
Hope it helps you