Question

the sum of three consecutive multiple of 6 is 888 find these multiples​

Answer 1

Step-by-step explanation:

Let 8n be the first multiple. Then the next multiple would be 8(n+1), and then 8(n+2). So:

8n+8(n+1)+8(n+2)=888

24n+24=888

24n=864

n=36

Then, the multiples of 8 are 36x8, 37 x 8, and 38 x 8, or** 288, 296, and 304**