Question

The sum of three consecutive multiple of 8 is 1080. Find these multiples​

Answer 1

Answer:Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Step-by-step explanation:Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

Answer 2

Question

The sum of three consecutive multiple of 8 is 1080. Find these multiples​.

$\rule{300}{1}$

Answer

Let the one multiple of 8 be ⇒ 8x

Second multiple of 8 would would be ⇒ 8 (x+1)

Third multiple of 8 would be ⇒ 8 (x+2)

So according to the question the three consecutive multiples of 8 sum up to 1080. Therefore, our equation would be ⇒ $8x+8(x+1)+8(x+2)=1080$

Let's solve your equation step-by-step.

$8x+8(x+1)+8(x+2)=1080$

Step 1: Simplify both sides of the equation.

$8x+8(x+1)+8(x+2)=1080$

(Distribute)

$8x+(8)(x)+(8)(1)+(8)(x)+(8)(2)=1080$

$8x+8x+8+8x+16=1080$

(Combine Like Terms)

$(8x+8x+8x)+(8+16)=1080$

$24x+24 =1080$

Step 2: Subtract 24 from both sides.

$24x+24-24=1080-24$

$24x=1056$

Step 3: Divide both sides by 24.

$\frac{24x}{24} =\frac{1056}{24}$

$x=44$

∴ The first multiple ⇒ 8 × 44 = 352

∴ The second multiple ⇒ 8 (44 + 1) = 8 × 45 = 360

∴ The third multiple ⇒ 8(44 + 2) = 8 × 46 = 368

When we add 352, 360 and 368 we get 1080.

∴ The three consecutive multiples of 8 that sum upto 1080 is 352, 360 and 368.

$\rule{300}{1}$