the sum of three consecutive multiple of 8 is 888 .find multiple
Answers
Answer:
Step-by-step explanation:
→ Let the first multiple of 8 be 8x.
→ Therefore the second consecutive multiple of 8 will be 8(x+1)
→ Also the third consecutive multiple of 8 will be 8(x+2).
→ It is given that the sum of these three consecutive multiples of 8 is 888
= 8x + 8(x+1) + 8(x+2) = 888
= 8x + 8x + 8 + 8x + 16 = 888
= 24x + 24 = 888
→ Take 24 on the RHS
= 24x = 888 - 24
= x = 864/24
= x = 36.
→ Therefore First multiple of 8 be 8x = 8 x 36 = 288
→ Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296
→ Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304
→ If we sum up these three multiples i.e (288 + 296 + 304) we get 888.
- Sum of three consecutive multiple of 8 is 888.
- The multiple
Let the first multiple be 8x.
Then the next two multiples are:-
8(x+1) and 8(x+2)
Therefore we found the value of x that is 36.
So,The first number is :-
Second number:-
Third number:-
Sum of the multiples is equal to 888.
A/Q
Hence,Verified.