the sum of three consecutive multiple of 8 is equals to eight times the sum of the first 2 consecutive multiple of 6. find each of the three multiple.
Answers
Step-by-step explanation:
Given:-
The sum of three consecutive multiple of 8 is equals to eight times the sum of the first 2 consecutive multiple of 6.
To find:-
Find each of the three multiples ?
Solution:-
Let the three consecutive multiples of 8
= 8X, 8X+8 , 8X+16
Their sum = 8X+8X+8+8X+16 = 24X+24
The sum of three consecutive multiples of 8
24X+24 ----------(1)
The first two consecutive multiples of 6
= 6 and 12
Their Sum =6+12= 18
The sum of two consecutive multiples of 6 =18------(2)
Given that
The sum of three consecutive multiple of 8 is equals to eight times the sum of the first 2 consecutive multiple of 6.
from (1)&(2)
=> 24X+24 = 8×18
=> 24X+24 = 144
=>24X = 144-24
=> 24X = 120
=> X = 120/24
=> X = 5
Now,
8X=8×5 = 40
8X+8 = 40+8 = 48
8X+16 = 40+16 = 56
Answer:-
The three consecutive multiples of 8 are 40,48,56
The first three multiples of 6 are 6,12,18
Check:-
The first two consecutive multiples of 6 = 6,12
Their sum = 6+12 = 18
The three consecutive multiples of 8 = 40,48,56
Their sum = 144
=>8×18
=> 8 times the sum of first two consecutive multiples of 6
Verified the given relations.