The sum of three consecutive multiple of 9 is 999. Find these multiples
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let the first multiple be x
A.T.Q
x + x + 9 + x + 18 =999
3x + 27 = 999
3x = 999- 27
3x = 972
x = 972/3
x = 324
Hence, the multiples are 324,333 and 342
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