Question

the sum of three consecutive multiple of 9 is 999 find these multiple​

Answer 1

Answer:

$\huge \pink{ \bold{Answer: - }}$

Step-by-step explanation:

Let the first consecutive mutiple be=x

Let the second consecutive multiple be=x+9

Let the third consecutive multiple be=x+18

Their sum=999

A.T.Q.

x+x+9+x+18=999

3x+27=999

3x=999-27

3x=972

x=972/3

x=324

First multiple=x=324

Second multiple=x+9=324+9=333

Third multiple=x+18=324+18=342

Check:-

x+x+9+x+18=999

324+333+342=999

999=999

L.H.S.=R.H.S.

Hence proved..

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