Question

The sum of three consecutive multiple of 9 is 999.. Find these multiple

:)plz answer​

Answer 1

Let the no. be x.

first multiple= X

second multiple= X+9

third multiple= X+18

Sum of these multiple =999

A/Q

X+X+9+X+18 = 999

3x+27 = 999

3x = 999-27

3x = 972

X = 972/3

X = 324

first multiple = 324

second multiple = 324+9=333

third multiple = 324+18=342

Hope it helps you...

Answer 2

Answer:

ʟᴇᴛ ᴛʜᴇ ᴛʜʀᴇᴇ ᴄᴏɴsᴇᴄᴜᴛɪᴠᴇ ᴍᴜʟᴛɪᴘʟᴇs ᴏғ 9 ʙᴇ

x,x+9,x+18

x+x+9+x+18=999

3x+27=999➪3x=999-27

3x=972➪x=972/3=324

ʜᴇɴᴄᴇ,ᴛʜᴇ ʀᴇǫᴜɪʀᴇᴅ ᴍᴜʟᴛɪᴘʟᴇs ᴏғ 9 ᴀʀᴇ 324,324+9=333 ᴀɴᴅ 333+9=342