the sum of three consecutive multiple s of11is 363 find the least multiple
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110 , 121 , 132
Step-by-step explanation:
let the three consecutive multiples of 11 be 11x , 11(x+1) , 11(x+2)
therefore,
11x + 11(x+1) + 11(x+2) =363
11x + 11x +11 + 11x + 22 = 363
33x + 33= 363
33x= 363 - 33
33x=330
x= 330/33
x= 10
therefore the three numbers are
11×10=110
11×12=132
11×11=121
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