the sum of three consecutive multiples is 11 is 363 find these multiples
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Answer:Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.
Step-by-step explanation:
Answered by
1
Answer:
110,121,132
Step-by-step explanation:
Let the multiples of 11 be
11x, 11(X+1), 11(X+2)
The sum of three consecutive multiples is 11 is 363. I,e
11x+ 11(X+1) + 11(X+2)= 363
11x +11x +11 +11x +22= 363
33x = 363-33
33x= 330
X= 330/33
X = 10
The multiples of 11 are
11*10= 110
(11+1)*10= 121
(11+2)*10= 132
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