Math, asked by sambramsalunle, 11 months ago

the sum of three consecutive multiples is 11 is 363 find these multiples​

Answers

Answered by thempara75
1

Answer:Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

Step-by-step explanation:

Answered by welltododevon
1

Answer:

110,121,132

Step-by-step explanation:

Let the multiples of 11 be

11x, 11(X+1), 11(X+2)

The sum of three consecutive multiples is 11 is 363. I,e

11x+ 11(X+1) + 11(X+2)= 363

11x +11x +11 +11x +22= 363

33x = 363-33

33x= 330

X= 330/33

X = 10

The multiples of 11 are

11*10= 110

(11+1)*10= 121

(11+2)*10= 132

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