Question

The sum of three consecutive multiples of 10 is 210. The smaller multiple is

Answer 1

Answer:

Step-by-step explanation:

Let the first multiple =x

Let the other multiple =x+10

Let the last multiple =x+20

Therefore, x+x+10+x+20=210

3x+30=210

3x=210-30

3x=180

x=180/3

x=60

First multiple = 60

Other multiple = 70

Last multiple =80

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