The sum of three consecutive multiples of 11 is 1023. find them
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Let 3 consecutive multiple of 11 be 11(x),11(x+1),11(x+2)
11x+11x+11+11x+22=1023
33x+33=1023
33x=1023-33
33x=990
X=990/33
X=30
Therefore,three consecutive multiples of 11 are 330,341,352
Now,you can add them to check wether I m wrong or right
11x+11x+11+11x+22=1023
33x+33=1023
33x=1023-33
33x=990
X=990/33
X=30
Therefore,three consecutive multiples of 11 are 330,341,352
Now,you can add them to check wether I m wrong or right
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