Question

the sum of three consecutive multiples of 11 is 1023 . find them

Answer 1

Let first number be x

2nd number be x+ 11

3rd number be x +22

( since they are multiples of 11)

X+11+x+22+x= 1023

3x+33= 1023

3x= 1023-33

3x= 990

X= 330

X+11= 330+11= 341

X+22= 330+22= 352

Therefore the numbers are 330,341 and 352

Answer 2

let the three consecutive multiple multiples of 11 be (11 x), (11 x + 1) and (11 X + 22).
A. T. Q,
11x + 11x + 11 + 11x + 22 = 1023
=>33x + 33 = 1023
=>33x = 1023-33
=>x = 990/33
=>x = 30.

Therefore the three consecutive multiples of 11 whose sum is 1023 are 330,343 and 354.


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