Question

The sum of three consecutive multiples of 11 is 1023 .fund them

Answer 1

Let the first number be x, then the second number would be x+11, and the third number would be x+22

Given that their sum is 1023

So, x + x+11 + x+22 = 1023

3x + 33 = 1023

3x = 1023-33

3x = 990

x = 990/3

x = 330 [1st number]

x+11 = 330+11 = 341 [2nd number]

x+22 = 330+22 = 352 [3rd number]

Hence, the three consecutive multiples of 11 are 330, 341 & 352 who's sum is 1023.

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Answer 2

Answer:

Answer is in attachment hope it helps