Question

the sum of three consecutive multiples of 11 is 198, find the numbers​

Answer 1

Answer:

Step-by-step explanation:

x+x+1x+2 = 198

3x+3=198

X=195÷3=65

Answer 2

Step-by-step explanation:

let the multiples be X

1 no - X

2 no - X + 11

3 no - X +22

X + X + 1 + x + 2 = 198

3x + 3 = 198

3x = 198 - 3

3x = 195

X = 195 ÷ 3

X = 65

1no = 65

2 no = 76

3 no = 87

here's your answer mate .

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