Question

The sum of three consecutive multiples of 11 is 264 find these multiples

Answer 1

Hey buddy :) your answer

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Let one multiple is 11x so another is 11(x+1)=11x+11 last one is 11(x+2)=11x+22

A/q 11x+11x+11+11x+22=264

=> 33x+33=264

=> 33x=264-33= 231

=> x= 231/33=7

Hence multiples are 11x=11×7 =77

11x+11=77+11=88

11x+22=77+22=99

Hope this helps you :)