Question

The sum of three consecutive multiples of 11 is 330 . Find the multiples

Answer 1

let first multiple is 11x where x=1,2,3,....
so second and 3rd multiple is 11x+11
and 11x+22
so sum=33x+33 =330
or x+1=10
or x=9
so the multiples are 99,110,121

Answer 2

let the multiples be 11x , 11x+11 ,11x+22
then a/q
11x + 11x+11+11x+22 =330
33x+33= 330
33x= 330-33
33x=297
x = 297/33
x = 9
so multiples are 99, 110, 121.