Question

the sum of three consecutive multiples of 11 is 330 find the multiples

Answer 1

Define x:

Let the smallest number be x

The 2nd number is x + 11

The 3rd number is x + 22

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STEP 2: Form the equation:

The sum of these 3 numbers is 330

x + (x + 11) + ( x + 22) = 330

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STEP 3: Solve x:

x + (x + 11) + ( x + 22) = 330

x + x + 11 + x + 22 = 330

3x + 33 = 330

3x = 297

x = 99

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STEP 4: Find the numbers:

smallest number = x = 99

2nd number = 99 + 11 = 110

3rd number = 99 + 22 = 121

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Answer: the three numbers are 99, 110 and 121

Answer 2

Hey there!!!

Let us take the first number as ' x '

Then the second number would be ' x + 11 '

Third number would be ' x + 22 '

Their sum is equal to 330

x + x + 11 + x + 22 = 330

3x + 33 = 330

3x = 330 - 33

3x = 297

x = 297 ÷ 3

x = 99

First number = 99

second number = 110

Third number = 121

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