Question

the sum of three consecutive multiples of 11 is 330 find the multiples.

Answer 1

let the multiples are 11x,11x+11,11x+22

then a/q
11x+11x+11+11x+22=330
33x+33=330
33x= 297
x = 297/33
x = 9
so multiples are 99,110,121

Answer 2

Answer:

Let 1st multiple=11x

2nd=11x+11

3rd=11x+22

A.q

11x+11x+11+11x+22=330

33x+33=330

33x=330-33

33x=297

x =297/33

= 9

1st multiple=9

2nd=9+11=20

3rd=9+22=31

Step-by-step explanation: