Question

The sum of three consecutive multiples of 11 is 363. Find them.​

Answer 1

Answer:

110, 121, 132

Step-by-step explanation:

11x+11(x+1)+11(x+2)=363

solve this

x=10

11x=110

11(x+1)=121

11(x+2)=132

Answer 2

first number be x=110

second number x+11=110+11=121

third number be x+22=110+22=132

Step-by-step explanation:

let x be the multiple of 11

first number be x

second number x+11

third number be x+22

$A/Q=x+(x+11)+(x+22)=363$

$x+x+11+x+22=363$

$3x+33=363$

$3x=363-33$

$3x=330$

$x=\frac{330}{3}$

$x=110$

first number be x=110

second number x+11=110+11=121

third number be x+22=110+22=132