Question

The sum of three consecutive multiples of 11 is 363. Find these multiples.

Answer 1

Acc. to question
(x+(x+11)+(x+12))= 363
33+3x=363
x=110

Answer 2

Three consecutive multiples are 110,121 and 132 which has the sum of 363.

Solution:

Let us take the first number as 11 (C – 1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 363

Now the sum of 3 numbers are 11C + 11(C – 1) + 11(C + 1) = 363

33C = 363;  C = 33,  

By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.