the sum of three consecutive multiples of 11 is 363. find these multiples
Answers
Answered by
629
Let the three consecutive multiples of 11 be 11x , 11(x + 1) and 11(x + 2)
11x + 11x + 11 + 11x + 22 = 363
33x = 363 - 33
33x = 330
so,
x = 10
hence,
the multiples are:
11x = 110
11(x+1)= 121
11( x + 2) = 132
11x + 11x + 11 + 11x + 22 = 363
33x = 363 - 33
33x = 330
so,
x = 10
hence,
the multiples are:
11x = 110
11(x+1)= 121
11( x + 2) = 132
ruhy:
simple answer
yaa
you can also take it as 11x+22x+33x=363
and solve it to get the value of x
Answered by
218
Let the three consecutive multiples of 11 be 11x , 11(x + 1) and 11(x + 2)
So, 11x + 11x + 11 + 11x + 22 = 363
or, 33x = 363 - 33
or, 33x = 330
or, x = 10
∴ The multiples are:
11x = 110
11(x+1)= 121
11( x + 2) = 132
So, 11x + 11x + 11 + 11x + 22 = 363
or, 33x = 363 - 33
or, 33x = 330
or, x = 10
∴ The multiples are:
11x = 110
11(x+1)= 121
11( x + 2) = 132
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