Question

the sum of three consecutive multiples of 11 is 363. find these multiples​

Answer 1

Step-by-step explanation:

3 consecutive multiples =(x-11), x, (x+11)

(x-11)+x+(x+11)=363

x-11+x+x+11=363

x+x+x-11+11=363

3x=363

x=363/3

x=121

x-11=121-11=110

x+11=121+11=132

So,

3 consecutive multiples =110, 121 and 132

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.