Question

The sum of three consecutive multiples of 11 is 363. find these multiplesl

Answer 1

let the small multiple be x

so another two are x+11&x+22

x+x+11+x+22=363

3x+33=363

3x=330

x=110

x+11=121

x+22=132

so three multiples are 110, 121, 132

Answer 2

HI !

Let the three consecutive multiples of 11 be "x" , "x+11" and "x + 22"

A.T.Q.,

x + x + 11 + x +22 = 363

3x + 33 = 363

3x = 330

x = 110

x + 11 = 121
x + 22 = 132

110 , 121 and 132 are the multiples of 11 , whose sum is 363