Question

The sum of three consecutive multiples of 11 is 363. Find these multiples,
(a) 117, 121, 125
(b) 110, 121, 132
(c) 110, 99, 154
(d) 154, 88, 121​

Answer 1

Answer:

Option B

Step-by-step explanation:

solution  to question

(x+(x+11)+(x+22))= 363

3x+33=363

3x  = 363 - 33

3x = 330

x = 330/3 = 110

x = 110

then , x+11 , means 110 + 11 = 121

        , x+22 , means 110 + 22 = 132

so done

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