The sum of three consecutive multiples of 11 is 363 . Find these multiples
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Answer:
the 3 consecutive multiples are 110 + 121 + 132 = 363
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sum of three consecutive multiples of 11 is 363
let the multiples be x, x+11, x+22
therefore x + x + 11 + x + 22 = 363
3x + 33 = 363
dividing the equation by 3 , we get
x + 11 = 121
x = 121-11
x = 110.
therefore the multiples are,
x = 110,
x + 11 = 121,
x + 22 = 132
110, 121, 132
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