Question

The sum of three consecutive multiples of 11 is 363. Find these multiples.
The sum of three consecutive positive integers is 39. Find these integers.
utive integers are such that taken in increasing order and mult
3.
1.
111​

Answer 1

Answer:

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Step-by-step explanation:

1) Acc. to question

(x+(x+11)+(x+12))= 363

33+3x=363

x=110

2) Let 3 consecutive positive integers be x-1,x,x+1

x-1+X+ X+1= 39

3x=39

X= 13

Hence these integers are 12,13,14

3)Answer:Three consecutive integers are 7,8 and 9

Solution:

Let the numbers are x, x+1 and x+2

(Since these are consecutive integers)

they are taken in increasing order and multiplied by 2,3 and 4 respectively

So x becomes 2x

(x+1) becomes 3(x+1)

(x+2) becomes 4(x+2)

they add up to 74,so ATQ

So,

Integers are 7,8,9

Verification:

Hence the calculate integers are correct.