The sum of three consecutive multiples of 11 is 363. Find these multiples.
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Answer:
11×11×11 = 1331
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Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22
Their sum is 363
11x+11x+11+11x+22=363
33x+33=363
33x=363−33
33x=330
x= 330/33
x=10
First multiple =11x=11×10= 110
Second multiple =11x+11=110+11= 121
Third multiple =11x+22=110+22= 132
Therefore, the 3 consecutive multiples of 11 are 110, 121, 132...
I hope this helps you...
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