The sum of three consecutive multiples of 11 is 363 find these multiples
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Answered by
11
11x + 11(x+1) + 11(x+2) = 363
11x + 11x + 11 + 11x + 22 = 363
33x + 33 = 363
33x = 330
x = 330/33
x = 10
11x + 11x + 11 + 11x + 22 = 363
33x + 33 = 363
33x = 330
x = 330/33
x = 10
deepali:
I think we will add 11 to it as these are not the consecutive numbers but consecutive multiples of 11
Answered by
3
the 3 multiples are 11,11x,11x+11 and their sum is 363 calculating this equation we get
11+11x+11x+11 =363
22+22x=363
22x=363- 22
22x=341
x=341/22
x= 15.5
11x= 11*15.5=170.5
11x+11= 170.5+11=181.5
so the three multiples are 11, 170.5, 181.5
11+11x+11x+11 =363
22+22x=363
22x=363- 22
22x=341
x=341/22
x= 15.5
11x= 11*15.5=170.5
11x+11= 170.5+11=181.5
so the three multiples are 11, 170.5, 181.5
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