Question

.The sum of three consecutive multiples of 11 is 363. Find these multiples.

Answer 1

Answer:

your answer with explaination

Step-by-step explanation:

let the three times consecutive multiples of 11 are 11x,11x+11 and 11x+22

their sum is 363.

11x+11x+11+11x+22=363

33x+33=363

33x=363-33

33x=330

X=330/33

X=10

first multiple=11x=11×10=110

second multiple=11x+11=100+11=121

third multiple=11x+22=110+22=132

Answer 2

Step-by-step explanation:

Alternatively,we may think of the multiple of 11 immediately before x.

This is (x-11). Therefore,we may take three consecutive multiples of 11 as

$x - 11$

$x$

$x + 11$

In this case we arrive at the equation

$(x - 11) + x + (x + 11) = 363$

$= > 3x = 363$

$= > x = \frac{363}{3} = 121$

Therefore,

• $x = 121$
• $x - 11 = 121 - 11 = 110$
• $x + 11 = 121 + 11 = 132$

Hence, The three consecutive multiples are:

110,121,132.