Question

.The sum of three consecutive multiples of 11 is 363. Find these multiples..The sum of three consecutive multiples of 11 is 363. Find these multiples.$.The sum of three consecutive multiples of 11 is 363. Find these multiples.$

Answer 1

The multiples are; ((110,121,132))

Step-by-step explanation:

let the three consecutive no. be (x-1),(x) & (x+1)

so, three consecutive multiples of 11 will be 11(x-1),11(x) & 11(x+1)

ATQ:— 11(x-1) + 11(x) + 11(x+1)= 363

=>11x-11+11x+11x+11=363

=>3×11x=363

=>x=11

so, the multiples are;

11(x-1),11(x) & 11(x+1)

=11(10) ,11(11) &,11(12)

=110,121,132

Answer 2

Answer:

Let the three consecutive multiples of 11 be 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=

33

330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132